An array A consisting of N integers is given. The dominator of array A is the value that occurs in more than half of the elements of A.
For example, consider array A such that
A[0] = 3 A[1] = 4 A[2] = 3 A[3] = 2 A[4] = 3 A[5] = -1 A[6] = 3 A[7] = 3
The dominator of A is 3 because it occurs in 5 out of 8 elements of A (namely in those with indices 0, 2, 4, 6 and 7) and 5 is more than a half of 8.
Write a function
class Solution { public int solution(int[] A); }
that, given an array A consisting of N integers, returns index of any element of array A in which the dominator of A occurs. The function should return −1 if array A does not have a dominator.
For example, given array A such that
A[0] = 3 A[1] = 4 A[2] = 3 A[3] = 2 A[4] = 3 A[5] = -1 A[6] = 3 A[7] = 3
the function may return 0, 2, 4, 6 or 7, as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [−2,147,483,648..2,147,483,647].
A에 포함되는 원소들에 대해 Count를 해야하기 때문에 HashMap 구조를 이용하였다. HashMap의 put, get, containsKey 은 O(1), worst O(n) 이기때문에 유용하다. (* containsValue = O(n) )
import java.util.*;
class Solution {
public int solution(int[] A) {
HashMap<Integer, Integer> cnt = new HashMap<>();
int half = A.length;
half /= 2;
if(A.length == 1){
return 0;
}
for(int i = 0; i < A.length; i++){
if(cnt.containsKey(A[i])){
cnt.put(A[i], cnt.get(A[i])+1);
if(cnt.get(A[i]) > half){
return i;
}
}
else{
cnt.put(A[i], 1);
}
}
return -1;
}
}
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